The degeneration of 3rd excited state of Li²+ is????
Answers
Explanation:
I think it is important to understand that for hydrogen atom (or any other one-electron system) all orbitals from the same shell have same energy. For instance, E2s=E2p, E3s=E3p=E3d, etc. Thus,
The first excited state of hydrogen atom would be one in which either 2s or one of the three 2p orbitals is occupied and it will be 4-fold degenerate: 1s02s1, 1s02p1x, 1s02p1y, 1s02p1z.
Analogously, the second excited state of hydrogen atom would be one in which either 3s or one of the three 3p or one of the five 3d orbitals is occupied and it will be 9-fold degenerate: 1s02s02p0x2p0y2p0z3s1, 1s02s02p0x2p0y2p0z3s03p1x, 1s02s02p0x2p0y2p0z3s03p1y, 1s02s02p0x2p0y2p0z3s03p1z, plus 5 configurations with only 3d-orbitals occupied.
Answer:
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Explanation: