Question

The degree in the given product is (1 Point)(x2+3)(x-1)

Answer 1

Answer:

(a) x

2

−3x+2=x

2

−2x−x+2=x(x−2)+1(x−2)=(x+1)(x−2)

(b) Since x

2

−3x+k can be written as the product of two first degree polynomials,

b

2

−4ac=0

(3)

2

−4(1)(k)=0⇒9−4k=0

k=9/4