Chemistry, asked by ghazala7937, 11 months ago

The degree of a hardness of a sample of water containing 6mg of mgso4 per kg is

Answers

Answered by sapnashu13
2

Answer:

Given, 1 kg of water contains 24 mg of MgSO4.

Given, 1 kg of water contains 24 mg of MgSO4.So 1 kg=1000 g of water.

Given, 1 kg of water contains 24 mg of MgSO4.So 1 kg=1000 g of water.1 million grams of water =1000×1000 g contains 24 mg×1000=24 g of MgSO4

Given, 1 kg of water contains 24 mg of MgSO4.So 1 kg=1000 g of water.1 million grams of water =1000×1000 g contains 24 mg×1000=24 g of MgSO41 mole of MgSO4=1 mole of CaCO3

Given, 1 kg of water contains 24 mg of MgSO4.So 1 kg=1000 g of water.1 million grams of water =1000×1000 g contains 24 mg×1000=24 g of MgSO41 mole of MgSO4=1 mole of CaCO3120 g of MgSO4=100 g of CaCO3

Given, 1 kg of water contains 24 mg of MgSO4.So 1 kg=1000 g of water.1 million grams of water =1000×1000 g contains 24 mg×1000=24 g of MgSO41 mole of MgSO4=1 mole of CaCO3120 g of MgSO4=100 g of CaCO324 g of MgSO4=(x) g of CaCO3

Given, 1 kg of water contains 24 mg of MgSO4.So 1 kg=1000 g of water.1 million grams of water =1000×1000 g contains 24 mg×1000=24 g of MgSO41 mole of MgSO4=1 mole of CaCO3120 g of MgSO4=100 g of CaCO324 g of MgSO4=(x) g of CaCO3So, x=12024×100=20

Given, 1 kg of water contains 24 mg of MgSO4.So 1 kg=1000 g of water.1 million grams of water =1000×1000 g contains 24 mg×1000=24 g of MgSO41 mole of MgSO4=1 mole of CaCO3120 g of MgSO4=100 g of CaCO324 g of MgSO4=(x) g of CaCO3So, x=12024×100=20So, degree of hardness =20 ppm

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Answered by sonuvuce
3

The degree of hardness of water sample is 5 ppm

Explanation:

The hardness of water is the concentration of multivalent cations

1 kg of water = 10⁻³ m³ of water = 1 lt of water

Wt of MgSO₄ = 6 mg

Molecular weight of MgSO₄= 120

Now,

Gram equivalents of MgSO₄ = Gram equivalents of CaCO₃

Weight of MgSO₄/Equivalent Weight of MgSO₄= Weight of CaCO₃/Equivalent weight of CaCO₃

or, (6 × 10⁻³)/(120/2) = Weight of CaCO₃/(100/2)

or, 10⁻⁴ = Weight of CaCO₃/50

or, Weight of CaCO₃ = 50 x 10⁻⁴

                                   = 5 × 10⁻³ gram

                                   = 5 mg

Thus, the hardness as of CaCO3 = 5 mg/lt = 5 ppm

Therefore, the degree of hardness of water sample = 5

Hope this answer is helpful.

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