The degree of hydrolysis of 0.1 M NHCl solution is 1% . If the concentration of NH4Cl is made 0.4M what is the new degree of hydrolysis...?
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degree of hydrolysis becomes half of initial
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Degree of hydrolysis = 0.5%
- Degree of hydrolysis h=sqrt(Kh/c)
- Kh = hydrolysis constant
- c = molar concentration
- Given that c1 = 0.1 M and c2 = 0.4 M, h1 = 1% and h2=?
- Kh is same for both cases.
- h1 = sqrt(Kh/c1)
- h2=sqrt(Kh/c2)
- h2/h1 = sqrt (Kh/c2)/sqrt(Kh/c1) = sqrt (c1/c2)
- h2 = h1*(sqrt(c1/c2)) = 1*(sqrt(0.1/0.4)) = 0.5 %
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