Chemistry, asked by deepbhagat434, 1 year ago

the degree of ionization of 0.4 acetic acid will be : kc = 1.8*10^-5

Answers

Answered by aayushg1713

1

Degree of ionization = √(ka / c) = √(1.8*10⁻⁵ / 0.4) = 5 * 10⁻⁴* √1.8 ≈ 6.70 * 10⁻⁴

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