Question

The degree of ionization of a 0.1M bromoacetic acid solution is 0.132. Calculate the pH of the solution and the p$K_{a}$ of bromoacetic acid.

Answer 1

Answer:

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Answer 2

$\bold {p^{k_a}\ of\ bromoacetic\ is\ 2.75}$

Explanation:

Degree of ionization, α = 0.132  

Concentration, c = 0.1 M

Thus,

the concentration of $H_3 O ^+ = c$

α = $0.1 \times 0.132$ = 0.0132

$P^H = - log[H^+]$

              = - log(0.0132)

              = 1.879:1.88

Now,

$K_a = c\times \alpha^2$

$K_a = 0.1\times (0.132)^2$

$K_a = 0.0017$

$p^{k_a} =  2.75$