Question

the degree of ionization of a 0.1M bromoacetic acidsolution in 0.132. calculate the pH of the solution and the pKa of the bromoacetic acid.

Answer 1

Degree of ionization, α = 0.132

Concentration, c = 0.1 M

Thus, the concentration of H3O+ = c.α

= 0.1 × 0.132

= 0.0132

=1.32*10$[^{-2}$

pH=-log$[H^{+}]$

    =-log(1.32)

    =2-0.1206

pH=1.88

Now,

Kₐ=cα²

   =0.1*(0.132)²

   =1.74*10⁻³

pKₐ=-log(1.74*10⁻³)

     =3-0.2405

     =2.76