Question

the degree of the polynomial p(x)=x+√x^2+1 is​

Answer 1

Answer:-✔✔↙️↙️

The degree of the polynomial is 1

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Answer 2

The degree of polynomial $\bf p(x) = x + \sqrt{ {x}^{2} } + 1$ is 1.

Given:

• A polynomial.
• $p(x) = x + \sqrt{ {x}^{2} } + 1$

To find:

• Find the degree of polynomial.

Solution:

Concept to be used:

Degree of polynomial is highest power of variable.A polynomial have powers as positive integers.

Step 1:

Simplify the polynomial.

$p(x) = x + ( {x}^{2})^{ \frac{1}{2} } + 1$

as

$\bf \sqrt{a} = {a}^{ \frac{1}{2} }$

Now,

It is written as

$p(x) = x + ( {x}^{ \cancel2})^{ \frac{1}{ \cancel2} } + 1$

or

$p(x) = x + x + 1$

Step 2:

Add similar terms.

$\bf p(x) =2x + 1$

It is clear that highest power of x is 1.

Thus,

Degree of p(x) is 1.

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Learn more:

1) Write the degree of the polynomial :

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