Question

The degree of the polynomial
$the \: degree \: of \: the \: polynomial \: \sqrt{2x { - 3x \times 1is \sqrt{2} }^{2} }$
2 x2-3x + 1 is a​

Answer 1

Answer:

ANSWER

sinA=msinB⟶(1)

tanA=ntanB

cosA

sinA

=n

cosB

sinB

⟶(2)

Substituting sinB from equation 1, we get

⟹cosB=

m

n

cosA⟶(3)

sin

2

A=m

2

sin

2

B

1−cos

2

A=m

2

(1−cos

2

B)

Substituting equation 3, we get

1−cos

2

A=m

2

(1−

m

2

n

2

cos

2

A),

cos

2

A=

n

2

−1

m

2

−1

(proved)

Answer 2

The degree of a polynomial \sqrt2 x^2-3x+12x2−3x+1 is 2.

Step-by-step explanation:

Given : Polynomial \sqrt2 x^2-3x+12x2−3x+1

To find : The degree of a polynomial ?

Solution :

The degree of a polynomial is defined as the degree of an individual term of a polynomial is the exponent of its variable.

Degree of individual term,

\sqrt2 x^22x2 degree is 2.

3x degree is 1.

1 degree is 0.

The highest degree is the required degree.

The degree of a polynomial \sqrt2 x^2-3x+12x2−3x+1 is 2.