Question

The denominator after rationalizing 7/(5root3-5root2)
A)19
B)20
C)25
D)none​

Answer 1

Step-by-step explanation:

Correct answer is option number (c).

HOPE IT HELPS YOU

Answer 2

Answer:

25

Step-by-step explanation:

$\frac{7}{5\sqrt{3}-5\sqrt{2} } =\frac{7(5\sqrt{3}+5\sqrt{2})}{(5\sqrt{3}-5\sqrt{2}) (5\sqrt{3}+5\sqrt{2}) } \\(using identity (a-b)(a+b)=a^{2}-b^{2} )\\=\frac{35\sqrt{3}+35\sqrt{2} }{(5\sqrt{3} )^{2} -(5\sqrt{2} )^{2}} =\frac{35\sqrt{3}+35\sqrt{2} }{75-50}}\\=\frac{35\sqrt{3}+35\sqrt{2} }{25}$

Hence,

Denominator after rationalizing= 25

Hope It Helps :)