Question

The denominator of a fractiom exceeds its numerator by 4. If the numerator snd denominator are both increased by 3, the the new fraction becomes 4/5 . Find the original fraction ? Plz answer it

Answer 1

Let, numerator be x
Denominator be y
A/Q, to 1st cond.
y= x+4 ........1

2nd cond.
x+3/y+3 = 4/5
5x + 15 = 4y + 12
5x - 4y + 3 = 0
5x -4(x+4) + 3 = 0
5x - 4x - 16 + 3 =0
x -13 = 0
x = 13

From 1
y = x + 4
y = 13 + 4
= 17

Answer 2

Answer:

The original fraction is 13 / 17

Step-by-step-explanation:

Let the numerator be x.

And the denominator be y.

Original fraction = x / y

From the first condition,

y = x + 4 - - ( 1 )

From the second condition,

( x + 3 ) / ( y + 3 ) = 4 / 5

=> 5 ( x + 3 ) = 4 ( y + 3 )

=> 5x + 15 = 4y + 12

=> 5x - 4y = 12 - 15

=> 5x - 4y = - 3

=> 5x - 4 ( x + 4 ) = - 3 - - ( From 1 )

=> 5x - 4x - 16 = - 3

=> x = - 3 + 16

=> x = 13

Put x = 13 in ( 1 )

y = x + 4

=> y = 13 + 4

=> y = 17

Numertaor ( x ) = 13

Denominator ( y ) = 17

Therefore,

The original fraction = 13 / 17