Question

the denominator of a fraction exceeds its numerator by 3 if 3 is added to both numerator and denominator the difference between the new and original fraction is 9 by 88. find the original no.

Answer 1

here is ur answer in image ---->

now the x cant be negative so the denominator is 8

and numerator is x+3
= 8+3 = 11.

so the fraction is 11/8.

hope it help u buddy .......

Answer 2

☆Hey Megha!!!!☆

===================
Here is your answer ☞
===================

$lets \: \\ numerator \: = x \\ therefor \: denominator \: = x + 3 \\ \\ fraction = \frac{x}{x + 3} \\ \\ according \: to \: your \: question \\ \\ new \: fraction = \frac{ x + 3}{x + 3 + 3} = \frac{x + 3}{x + 6} \\ \\ according \: to \: given \: condition \\ \\ = > \frac{x + 3}{x + 6} - \frac{x}{x + 3} = \frac{9}{88} \\ \\ = > \frac{ {(x + 3)}^{2} - x(x + 6)}{(x + 6)(x + 3)} = \frac{9}{88} \\ \\ = > \frac{ {x}^{2} + 9 + 6x - {x}^{2} - 6x}{ {x }^{2} + 9x + 18} = \frac{9}{88} \\ \\ = > {x}^{2} + 9x + 18 = 88 \\ \\ = > {x}^{2} + 9x - 70 = 0 \\ \\ = > {x}^{2} + 14x - 5x - 70 = 0 \\ \\ = > x(x + 14) - 5(x + 14) = 0 \\ \\ = > (x - 5)(x + 14) = 0 \\ \\ = > x = - 14...(not \: a \: possible \: value) \\ \\ = > x = 5 \: \: \: \: ....numerator \\ \\ then \\ \\ = > x + 3 = 5 + 3 \\ = 8 \: \: \: \: \: ......denominator$


Hence, your answer is "5/8"

==================
Hope it will help you ☺☺☺
==================

Devil_king ▄︻̷̿┻̿═━一