Question

the denominator of a fraction exceeds its numerator by 4. if the numerator and denominator are both increased. by 3 the new fraction becomes 4/5. Find the original fraction
​

Answer 1

HEYA!!!!!

Here is your answer :

__________________________

let the numerator be x

Denominator be x + 4

If the numerator and Denominator increased by 3 then,

The fraction = 4/5

ATP,

Therefore, the original fraction :

HOPE THIS HELPS YOU.

Answer 2

Step-by-step explanation:

AnswEr:

Let us Consider that the Numerator be x and the Denominator be x + 4.

According to Question,

If the Numerator & Denominator are both increased by 3 fraction becomes $\sf\dfrac{4}{3}.$

So,

$\implies\sf\; \dfrac{x +3}{x + 4 + 3} = \dfrac{4}{3}$

$\implies\sf\; \dfrac{x + 3}{x + 7} = \dfrac{4}{3}$

$\:\:\:\:\:\:\:\:\:\:\:\dag\:\footnotesize\bold{\underline{\underline{\sf{\purple{Now,\: Cross\; Multiplying}}}}}$

$\implies\sf\; 3(x +3) = 4(x +7)$

$\implies\sf\; 3x + 9 = 4x + 28$

$\implies\sf\; 3x - 4x = 28 - 9$

$\implies\sf -x = 19$

$\implies\sf\bold\red{x \:=\: -19}$

$\rule{150}2$

$\implies\sf\; Numerator\: = \;x\: = \: -19$

$\implies\sf\; Denominator\: =\: x\; +\: 4\; =\; -19 \;+ \;4$

$\implies\sf\; -15$

$\implies\sf \dfrac{-19}{-15}$

Hence, The Required Fraction is $\sf\red{\dfrac{19}{15}}.$