Question

the denominator of a fraction exceeds its numerator by 8.if the numerator is increase by 17 and the denominator is decreased by 1,we get 3:2 find the original fraction?​

Answer 1

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Answer 2

Answer:

$\frac{13}{21}$

Step-by-step explanation:

Let the numerator be x

We are given that the denominator of a fraction exceeds its numerator by 8

So, Denominator = x+8

Original Fraction =$\frac{x}{x+8}$

Now we are given that  the numerator is increase by 17 and the denominator is decreased by 1 So, we get 3:2

So, $\frac{x+17}{x+8-1}=\frac{3}{2}$

$\frac{x+17}{x+7}=\frac{3}{2}$

$2x+34=3x+21$

$34-21=x$

$13=x$

So, Original Fraction =$\frac{13}{13+8}=\frac{13}{21}$

Hence  the original fraction is $\frac{13}{21}$