Question

the denominator of a fraction exceeds its numerator by 8.if the numerator is increase by 17 and the denominator is decreased by 1,we get 3/2 find the original fraction?​

Answer 1

Answer:

Step-by-step explanation:

Given :-

The denominator of a fraction exceeds its numerator by 8.

If the numerator is increase by 17 and the denominator is decreased by 1, we get 3/2.

To Find :-

The Original Fraction

Solution :-

Let the numerator be x.

And the denominator be x + 8

Fraction = x / x + 8

According to the question,

x + 17 / x + 8 - 1 = 3 / 2

⇒ x + 17 / x + 7 = 3 / 2

⇒ 3 ( x + 7 ) = 2 ( x + 17 )

⇒ 3x + 21 = 2x + 34

⇒ 3x - 2x = 34 - 21

⇒ x = 13

Original fraction = x / x + 8

= 13 / 13 + 8

= 13 / 21

Hence, the original fraction is 13 / 21

Answer 2

Answer:

pedhiyila povane sethapayale naarapayale

Step-by-step explanation:

chaavu nakku