Question

the denominator of a fraction exceeds the numerator by 3 and if the numerator be increased by 7,the fraction is increased by unity,find the fraction​

Answer 1

Answer:

The fraction is 4/7.

Step-by-step explanation:

Let the numerator be x then the denominator is x+3. The fraction is x/(x+3).

If the numerator is increased by 7 ie. x+7, the fraction is increased by unity.

(x+7)/(x+3) = x/(x+3) + 1

(x+7)/(x+3) = (x+x+3)/(x+3)

x+7 = 2x+3

x= 4.

Therefore, the fraction is 4/7.

Answer 2

Step-by-step explanation:

mark me as brilliant.

like and suscribe