Question

the denominator of a fraction is 1 less than twice the numerator . if numerator is increased by 3 and the denominator is increased by 7, what is the new value fraction
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Answer 1

Answer:

Let the fraction be = x/y

Given:

y = 2x - 1 ..(1)

To find:

(x + 3)/(y + 7)

=> (x + 3)/(2x - 1 + 7)

=> (x + 3)/(2x + 6)

Take 3 common from the denominator:

=> (x + 3)/3(x + 3)

(x + 3) cancel:

=> 1/2

Thank You!

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Answer 2

Answer

3x÷(7x-1)

Step-by-step explanation:

LET THE NUmerator be x

∴atq

x-1=the denominator

⇒the fraction is  x÷(x-1)

now 3×x÷(7(x-1))

=3x÷(7x-7)