Question

the denominator of a fraction is 1 more than twice its numerator. if the numerator and denominator are both increased by 5 , it becomes 3/5 . find the original fraction​

Answer 1

Supposition:-

let the numerator be X.

let the denominator be 2x+1

According to the question:-

$\sf\dfrac{X+5}{2x+1+5}$ = $\sf\dfrac{3}{5}$

$\sf{\: 5(X+5)}$ = $\sf{\: 3(2x+1+5)}$

$\sf{\: 5x+25}$ = $\sf{\: 6x+18}$

$\sf{\: 7}$ = $\sf{\: X}$

so, the numerator becomes 7

denominator becomes = 2(7)+1 = 15.

hence, the original fraction is $\sf\dfrac{7}{15}$

Answer 2

Answer:

7/3

Step-by-step explanation:

so, the numerator becomes 7

denominator becomes = 2(7)+1 = 15.

hence, the original fraction is  7/3