Question

The denominator of a fraction is 2 less than five times the numerator. When both the numerator and denominator are decreased by 3 , the denominator becomes 10 times the numerator. Find the fraction​

Answer 1

Answer:

Ans ⅝

Step-by-step explanation:

Answer:

The fraction is \frac{5}{8}

8

5

Step-by-step explanation:

Let the numerator be N and denominator be D

So, the required fraction will be \frac{N}{D}

D

N

According to question,

The numerator of a fraction is 3 less than denominator, that is ,

N = D - 3

So, the new fraction is \frac{D-3}{D}

D

D−3

Also, it is given that if 1 is added to both its numerator and denominator it becomes 2 / 3

Therefore now,

\frac{D-3+1}{D+1} = \frac{2}{3}

D+1

D−3+1

=

3

2

\frac{D-2}{D+1} = \frac{2}{3}

D+1

D−2

=

3

2

3 ( D - 2 ) = 2 ( D + 1 )

3 D - 6 = 2 D + 2

3 D - 2 D = 2 + 6

D = 8

We know,

N = D - 3

N = 8 - 3 = 5

So the fraction \frac{N}{D}

D

N

= \frac{5}{8}

8

5

Hence,

The fraction is \frac{5}{8}

8

5