Question

the denominator of a fraction is 2 more than its numerator.if one is added to both the numerator and their denominator the fraction becomes 2/3, find the fraction

Answer 1

Let the numerator be x
Then the denominator will be x+2
ATQ
=>x+1/x+2+1=2/3
=>x+1/x+3=2/3
=>3 (x+1)=2 (x+3)
=>3x+3=2x+6
=>3x-2x=6-3
=>x=3

The fraction is 3/5.

HOPE IT HELPS...!!

Answer 2

Answer:

$\frac{3}{5}$

Step-by-step explanation:

Let the numerator be x

We are given that the denominator of a fraction is 2 more than its numerator.

So, Fraction = $\frac{x}{x+2}$

Now we are given that if one is added to both the numerator and their denominator the fraction becomes 2/3,

So, $\frac{x+1}{x+2+1}=\frac{2}{3}$

$\frac{x+1}{x+3}=\frac{2}{3}$

$3(x+1)=2(x+3)$

$3x+3=2x+6$

$3x-2x=6-3$

$x=3$

So, numerator = 3

Denominator = x+2=3+2=5

Fraction: $\frac{3}{5}$