Question

the denominator of a fraction is 2 more than the numerator . if 1 is added to both, the fraction reduces to 4/3. find fraction

Answer 1

Let the numerator be x.

Then the denominator will be x + 2.

Therefore the original fraction = x/x + 2.  ------- (1)

Given that 1 is added to both, the fraction reduces to 4/3.

$\frac{x + 1}{x + 2 + 1} = \frac{4}{3}$

$\frac{x + 1}{x + 3} = \frac{4}{3}$

3(x + 1) = 4(x + 3)

3x + 3 = 4x + 12

3x = 4x + 9

x = -9.

Substitute in (1), we get

Therefore the original fraction = $\frac{-9}{-7}$.


Verification:

$\frac{-9 + 1}{-9 + 3} = \frac{4}{3}$

$\frac{-8}{-6} = \frac{4}{3}$

$\frac{4}{3} = \frac{4}{3}$


Note: Kindly check ur question, i think its incorrect.


Hope this helps!

Answer 2

Hi,

Please see the attached file!


Thanks