Question

The denominator of a fraction is 3 less than the numerator.
Increasing the numerator by 4and decreasing the denominator by 3, we get the number 3
Find the fraction.​

Answer 1

Answer:

let the denomination be x

the numerator be x+3

after increasing 4 the numerator becomes x+3+4

=x+7

after decreasing 3 denomination becomes x-3

x+7/x-3=3

x+7=3(x-3)

x+7=3x-9

x-3x=-9-7

-2x=-16

2x=16

x=16/2

x=8

Answer 2

Given :

• Denominator of a fraction is 3 less than the numerator.
• If numerator is increased by 4 and denominator is decreased by 3 then the number obtained is 3 .

To Find :

• The Fraction .

Solution :

$\longmapsto\tt{Let\:Numerator\:be=x}$

As Given that Denominator of a fraction is 3 less than the numerator. So ,

$\longmapsto\tt{Denominator=x-3}$

Now ,

• If numerator is increased by 4 and denominator is decreased by 3 then the number obtained is 3 .

$\longmapsto\tt{Numerator=x+4}$

$\longmapsto\tt{Denominator=x-3-3=x-6}$

A.T.Q :

$\longmapsto\tt{\dfrac{x+4}{x-6}=\dfrac{3}{1}}$

$\longmapsto\tt{1(x+4)=3(x-6)}$

$\longmapsto\tt{1x+4=3x-18}$

$\longmapsto\tt{1x-3x=-18-4}$

$\longmapsto\tt{-2x=-22}$

$\longmapsto\tt{x=\cancel\dfrac{-22}{-2}}$

$\longmapsto\tt\bf{x=11}$

Value of x is 11 ..

Therefore :

$\longmapsto\tt\bf{Numerator=11}$

$\longmapsto\tt{Denominator=11-3}$

$\longmapsto\tt\bf{8}$

So , The Fraction is 11/8 ..