Question

The denominator of a fraction is 3 more than the numerator. If 1 is subtracted from both numerator and denominator, the resulting fraction has a value of 1/2. Find the original fraction...

Omhayghad pls...help me

Answer 1

Answer:

(x-1/(x+3) -1) =1/2

2x-2=x+3-1

x=4

Answer 2

Answer :-

$\dfrac{4}{7}$

Given :-

$d = 3 + n$

$\dfrac{d-1}{n-1}= \dfrac{1}{2}$

To find :-

The value of original fraction.

Solution:-

Let the numerator be n and denominator be d.

→$d = 3 + n ----1)$

→$\dfrac{n-1}{d-1}= \dfrac{1}{2}$

→$2 (n-1) = d -1$

→$2n -2 = d -1$

→$2n - d = -1 +2$

→$2n - d = 1 ----2)$

• Put the value of d in eq.2

→$2n - (3+n) = 1$

→$2n - 3 -n = 1$

→$n = 1 + 3$

→$n = 4$

• Put the value of n in eq.1

→$d = 3 + n$

→$d = 3 + 4$

→$d = 7$

hence,

The required original fraction is $\dfrac{4}{7}$