The denominator of a fraction is 3 more than the numerator if 2 added to numerator and 5 added to denominator the fraction become 1/2 find the fraction.
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Answered by
20
Let the numerator be x.
Then the denominator will be 3 more than the numerator = x + 3.
The original fraction = x/x + 3 --------------------- (1)
Given that if 2 is added to numerator and 5 is added to the denominator, the fraction becomes 1/2.
(x + 2)/(x + 3) + 5 = 1/2
x + 2/x + 3 + 5 = 1/2
x + 2/x + 8 = 1/2
2(x + 2) = x + 8
2x + 4 = x + 8
2x = x + 8 - 4
2x = x + 4
2x - x = 4
x = 4.
Substitute x = 4 in (1), we get
The fraction = 4/7.
Therefore the original fraction = 4/7.
Verification:
(x + 2)/(x + 3) + 5 = 1/2
(4 + 2)/(4 + 3) + 5 = 1/2
6/7 + 5 = 1/2
6/12 = 1/2
1/2 = 1/2.
Hope this helps!
Then the denominator will be 3 more than the numerator = x + 3.
The original fraction = x/x + 3 --------------------- (1)
Given that if 2 is added to numerator and 5 is added to the denominator, the fraction becomes 1/2.
(x + 2)/(x + 3) + 5 = 1/2
x + 2/x + 3 + 5 = 1/2
x + 2/x + 8 = 1/2
2(x + 2) = x + 8
2x + 4 = x + 8
2x = x + 8 - 4
2x = x + 4
2x - x = 4
x = 4.
Substitute x = 4 in (1), we get
The fraction = 4/7.
Therefore the original fraction = 4/7.
Verification:
(x + 2)/(x + 3) + 5 = 1/2
(4 + 2)/(4 + 3) + 5 = 1/2
6/7 + 5 = 1/2
6/12 = 1/2
1/2 = 1/2.
Hope this helps!
siddhartharao77:
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Answered by
14
hello!
Let the numerator be x.
Let the denominator be x+3
The fraction is x/x+3
BTP,
(x+2)/(3+x+5)=1/2
=>2 (x+2)=x+8
=>2x+4=x+8
=>x=4
fraction is 4/7
hope it helps... :)
Let the numerator be x.
Let the denominator be x+3
The fraction is x/x+3
BTP,
(x+2)/(3+x+5)=1/2
=>2 (x+2)=x+8
=>2x+4=x+8
=>x=4
fraction is 4/7
hope it helps... :)
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