the denominator of a fraction is 4 less than its numerator if 6 is added to the numerator it becomes thrice the denominator find the fraction solve
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let x be numerator
then denominator=x-4
a/q
X+6=3(x-4)
X+6=3x-12
2x=18
X=9
therefore numerator=9 and denominator=9-4=5
hence required fraction is 9/5
then denominator=x-4
a/q
X+6=3(x-4)
X+6=3x-12
2x=18
X=9
therefore numerator=9 and denominator=9-4=5
hence required fraction is 9/5
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