Question

the denominator of a fraction is 4 more than it's numerator on subtracting 1 from each other numerator and denominator the fraction become 1/2 find the original fraction

who will ans I will mark it as brainliest​

Answer 1

Answer:

$\bigstar{\bold{Original\:Fraction=\dfrac{3}{7} }}$

Step-by-step explanation:

$\Large{\underline{\underline{\sf{Given:}}}}$

• Denominator of the fraction = 4 more than its numerator
• Subrtracting 1 each from numerator and denominator, fraction becomes 1/2

$\Large{\underline{\underline{\sf{To\:Find:}}}}$

• The original fraction

$\Large{\underline{\underline{\sf{Solution:}}}}$

→ Let the numerator of the fraction be x

→ By given,

  Denominator of the fraction = 4 + x

→ Hence the fraction would be x / (4+x)

→ By given adding 1 to numerator and denominator, the fraction would become 1/2

→ Hence,

  (x + 1)/(5 + x) = 1/2

→ Cross multiplying,

  5 + x = 2 ( x + 1)

  5 + x = 2x + 2

  2x - x + 2 = 5

  x = 5 - 2

  x = 3

→ Hence the numerator of the fraction is 3

→ By given,

  Denominator = 4 + x

  Denominator = 4 + 3

  Denominator = 7

→ Hence denominator of the fraction is 7

→ Hence the fraction is 3/7

  $\boxed{\bold{Original\:Fraction=\dfrac{3}{7} }}$

$\Large{\underline{\underline{\sf{Verification:}}}}$

→ Denominator = Numerator + 4

  7 = 4 + 3

  7 = 7

→ Adding 1 to numerator and denominator, fraction = 1/2

  3 + 1/ 7 + 1

 = 4/8

 = 1/2

→ Hence verified.