the denominator of a fraction is 4 more than its numerator .on subtracting 1from each numerator and the denominator the fraction becomes 5/7.find the original fraction
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let x be the numerator and y be the denomination
x+4=y______1
x-1/y-1=5/7_____2
2=. 5(y-1)=7(x-1)
5y-5=7x-7
7x-5y-7+5=0
7x-5y-2=0______3
solving equation 1 and 3 by elimination method
eqn1×5= 5x-5y+20=0
eqn3×1=7x-5y-2=0
- +. +
________
-2x +0y +22=0
x=22/2
x=11
substitute x=11 in eqn 1
y=15
therefore fraction is 11/15
x+4=y______1
x-1/y-1=5/7_____2
2=. 5(y-1)=7(x-1)
5y-5=7x-7
7x-5y-7+5=0
7x-5y-2=0______3
solving equation 1 and 3 by elimination method
eqn1×5= 5x-5y+20=0
eqn3×1=7x-5y-2=0
- +. +
________
-2x +0y +22=0
x=22/2
x=11
substitute x=11 in eqn 1
y=15
therefore fraction is 11/15
michael66:
l have not understood the elimination method please solve in other method
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