Question

the denominator of a fraction is 9 more than its numerator if numerator and denominator both are increased by 7 the new feaction become 7÷10 found orignal fraction​

Answer 1

Let assume denominator = x+9 and numerator Now increases numerator and denominator by 7

so we get

X+7/(x+9+7) = x+7/ x+16 and now compare the

ans and fraction given we get

X+7/x+16=7/10

10x+70=7x +112

10x-7x = 112-70

3x =42

X=42/3

X=14

So the original fraction = 14/23

Answer 2

Answer:

Let initially numerator is x

and denominator as y

$then \: y = x + 9$

now if 7 is added to both numerator and denominator then the fractions become

$=> \frac{(x + 7)}{(y + 7)} = \frac{7}{10}$

$=> \frac{(x + 7)}{(x + 16)} = \frac{7}{10}$

$= 10x + 70 = 7x + 96$

$3x = 26$

$x = \frac{26}{3}$

$= \frac{26}{3} + 9$

$y = \frac{26 + 27}{3}$

$y = \frac{53}{3}$

therefore original fraction is

$\frac{x}{y} = \frac{ \frac{26}{3} }{ \frac{53}{3} } = \frac{26}{53}$