The denominator of a fraction is greater than its numerator by 11. If 8 is added to both numerator and denominator, it becomes 3÷4 Then the original fraction is
Answers
Answer :
⟶ Original fraction = 9 / 20
Explanation :
According to the condition :
Let numerator be ' n ' and denominator be ' d '
According to the question :
- Denominator ( d ) = ( 11 + n )
- Numerator ( n ) = 8 is added = ( n + 8 )
- Denominator ( d ) = ( 11 + n ) + 8
- Answer = 3 / 4 { given }
⟶ N / D = N / D
Equation :
⟹ n + 8 / ( 11 + n ) + 8 = 3 / 4
↪cross multiply ✖
⟹ 4 ( n + 8 ) = 3 ( 11 + n ) + 8
⟹ 4n + 32 = ( 33 + 3n ) + 8
⟹ 4n - 3n = ( 33 - 32 ) + 8
⟹ 1n = 1 + 8
⟹ n = 9
To find :
➳ Numerator ( n ) = 9
➳ Denominator ( d ) = ( 11 + n ) = 11 + 9 = 20
➳ The original fraction = 9 / 20
So, It's Done !!
The denominator of a fraction is greater than its numerator by 11. If 8 is added to both numerator and denominator, it becomes 3/4 Then the original fraction is
Let, x be the numerator & y be the denominator.
• Numerator = x
• Denominator = y
{ According to question}
• Denominator = y = x + 11 ......( 1 )
8 is added to both numerator and denominator .
• Numerator = x + 8 ...... ( 2 )
• Denominator = ( x + 11 ) + 8 ....( 3 )
Fraction of Numerator & Denominator becomes 3/4 ..{ From ( 2 ) & ( 3 ) }
Put value of x in equation ( 1 )
• Denominator = y = x + 11
• Denominator = y = 25 + 11
• Denominator = y = 36
Hence fraction of Numerator & Denominator is 25/36
i hope it helps you.