Question

The denominator of a fraction is greater than the numerator by3. If 7is added to the numerator., the fraction increases by unity. Find the fraction.

Answer 1

$using \: \: x........ \\ \frac{x}{x + 3} = \frac{x + 7}{x + 3} + 1 \\ = > \frac{x}{x + 3} - \frac{x + 7}{x + 3} = 1 \\ = > \frac{(x - x + 7)}{x + 3} = 1 \\ = > 7 = x + 3 \\ = > x + 3 = 7 \\ = > x = 7 - 3 \\ = > x = 4. \\ the \: \: required \: \: fraction \: \: is \\ \frac{4}{4 + 3} = \frac{4}{7} .$
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