Math, asked by SHIVAMDHASMANA, 8 hours ago

The denominator of a fraction is greater than the numerator by 8. If the numerator is increased by 17 and denominator is decreased by 1, the number obtained is 3/2. Find the fraction.

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Answers

Answered by Ladylaurel
56

Answer :-

The fraction is 13/21.

Step-by-step explanation:

To Find :-

  • The fraction.

Solution

Given,

Denominator of a fraction is greater than the numerator by 8.

Therefore, Let us assume the numerator as (x) and denominator as (x + 8).

The fraction is \bf{\dfrac{x}{(x + 8)}}

Also given, The numerator is increased by 17. The Denominator is decreased by 1. And the fraction or number obtained is 3/2.

Hence, The new numerator and denominator is :-

Numerator :-

(x) + 17

(x + 17)

Denominator :-

(x + 8) - 1

(x + 7)

According the question,

Given, The fraction: \boxed{\sf{\dfrac{(x + 17)}{(x + 7)} = \dfrac{3}{2}}}

By simplifying,

\sf{\mapsto \: \dfrac{(x + 17)}{(x + 7)} = \dfrac{3}{2}}

By cross multiplication,

\sf{\longmapsto \: 3(x + 7) = 2(x + 17)}

\sf{\longmapsto \: 3(x + 7) = 2(x + 17)}

\sf{\longmapsto \: 3x + 21 = 2x + 34}

\sf{\longmapsto \: 3x = 2x + 34 - 21}

\sf{\longmapsto \: 3x = 2x + 13}

\sf{\longmapsto \: 3x - 2x = 13}

\sf{\longmapsto \: x = 13}

The value of x is 13.

Now, The fraction is :-

We assumed the numerator and denominator as (x) and (x + 8).

\sf{\longmapsto \: \dfrac{(x)}{(x + 8)}}

\sf{\longmapsto \: \dfrac{13}{(13 + 8)}}

\bf{\longmapsto \: \dfrac{13}{21}}

Hence, The fraction is 13/21.

Answered by kashaf980769
4

Answer:

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