the denominator of a fraction is two more than its numerator. if the sum of the fraction and it's reciprocal is 34/15 find the fraction
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Let the numerator be x and denominator be x+2.
Required fraction = x/x+2
According to the question,
x/x+2 + x+2/x = 34/15
x^2 + (x+2)^2/x^2 + 2x = 34/15
x^2 + x^2 + 4x + 4/x^2 + 2x = 34/15
(2x^2 + 4x + 4)×15 = 34×(x^2 + 2x)
30x^2 + 60x + 60 = 34x^2 + 68x
34x^2 + 68x - 30x^2 - 60x - 60 = 0
4x^2 + 8x - 60 = 0
x^2 + 2x - 15 = 0
x^2 + 5x - 3x - 15 = 0
x (x + 5) - 3 (x + 5) = 0
(x + 5) + (x - 3) = 0
So, x + 5 = 0 or x - 3 = 0
x = -5 or x = 3
For x = -5,
x/x + 2 = 5/3
For x = 3,
x/x + 2 = 3/5
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