Question

the denominator of a ratioal number is greater than its numerator by 3 if 3 is subtracted from luminator and 2 is added to its denominator the new number becomes 1 upon 5 find the original number.
Please give with explanation
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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Let,

Numerator be x

Denominator be (x +3)

Fraction = x/(x+3)

----------------------------

According to the question,

\frac{x - 3}{x + 3 + 2} = \frac{1}{5}

x+3+2

x−3

=

5

1

\begin{gathered}\frac{x - 3}{x + 5} = \frac{1}{5} \\ \\ 5(x - 3) = 1(x + 5) \\ \\ 5x - 15 = x + 5 \\ \\ 5x - x = 5 + 15 \\ \\ 4x = 20 \\ \\ x = \frac{20}{4} \\ \\ x = 5\end{gathered}

x+5

x−3

=

5

1

5(x−3)=1(x+5)

5x−15=x+5

5x−x=5+15

4x=20

x=

4

20

x=5

Then,

fraction = \frac{5}{5 + 3} = \frac{5}{8}fraction=

5+3

5

=

8

5

I hope this will help you