Question

The denominator of a rational no es greater
than its numerator by 8. of the numerator
es Encreased by 17
and the denominators
is decreased by I, the no obtained es 3.
Send the no.
2.
Solutions​

Answer 1

Correct question :

The denominator of a Rational number is greater than its numerator by 8. Numerator is increased by 17 and Denominator is decreased by 1, the number obtained is 3 / 2. Find the numbers?

Solution :

Given :

• The denominator of a Rational number is greater than its numerator by 8.

• Numerator is increased by 17

• Denominator is decreased by 1

• Number obtained is 3 / 2

To find :

• Find the number

According to the question :

• Let the Numerator be ' n '

It is given that, Denominator is greater than the numerator (n) by 8

• Denominator will be ' ( n + 8 ) '

We know that, a fraction is Numerator (n) / Denominator (d)

• The number will be = n / n + 8 ...... (1)

Then, Numerator increased by 17. Numerator was (n)

• n + 17

Denominator decreased by 1, already the denominator = ( n + 8 )

• ( n + 8 - 1 )

Equation would be,

⟹ n + 17 / ( n + 8 - 1 ) = 3 / 2

⟹ n + 17 / n + 9 = 3 / 2

⟹ 2 ( n + 17 ) = 3 ( n + 7 )

⟹ 2n + 34 = 3n + 21

⟹ 3n - 2n = 34 - 21

⟹ 1n = 13

⟹ n = 13

Substituting ' n ' value in (Eq 1),

⟹ n / n + 8

⟹ 13 / 13 + 8

⟹ 13 / 21

The fraction is 13 / 21

So Its Done !!