the denominator of a rational no. is greater than its numerator by 7 . if the numerator is increased by 19 and the denominator is decreased by 3, the new number becomes 4. find the original no.
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Hey Mate !
Here is your solution :
Let the numerator is x.
So, denominator = ( x + 7 ).
Fraction = Numerator / Denominator = x / ( x + 7 ).
A/Q,
If we add 19 to the numerator of number and subtract 3 from the denominator it becomes 4.
=> ( x + 19 ) / ( x + 7 - 3 ) = 4
=> ( x + 19 ) / ( x + 4 ) = 4
=> ( x + 19 ) = 4 ( x + 4 )
=> x + 19 = 4x + 1t
=> 19 - 16 = 4x - x
=> 3 = 3x
=> x = ( 3/3 ) = 1
Numerator = x = 1
Denominator = ( x + 7 ) = 1 + 7 = 8
Fraction = x / ( x + 7 )
= 1/8
Hence , the required answer is ( 1/8 ).
=============================
Hope it helps !! ^_^
Here is your solution :
Let the numerator is x.
So, denominator = ( x + 7 ).
Fraction = Numerator / Denominator = x / ( x + 7 ).
A/Q,
If we add 19 to the numerator of number and subtract 3 from the denominator it becomes 4.
=> ( x + 19 ) / ( x + 7 - 3 ) = 4
=> ( x + 19 ) / ( x + 4 ) = 4
=> ( x + 19 ) = 4 ( x + 4 )
=> x + 19 = 4x + 1t
=> 19 - 16 = 4x - x
=> 3 = 3x
=> x = ( 3/3 ) = 1
Numerator = x = 1
Denominator = ( x + 7 ) = 1 + 7 = 8
Fraction = x / ( x + 7 )
= 1/8
Hence , the required answer is ( 1/8 ).
=============================
Hope it helps !! ^_^
Anonymous:
Mjhe pata hay
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