The denominator of a rational number is greater than it's numerator by 3 . If the numerator is increased by 7 and denominator decreases by 1 the new number is 3/2. Find the original number
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Answered by
0
hi frnd
let numerator =x
denominator =x+3
number=x/x+3
If the numerator is increased by 7 and denominator decreases by 1 the new number is 3/2
so,x+ 7/x+3-1=3/2
x+7/x+2=3/2
2(x+7)=3(x+2)
2x+14=3x+6
3x-2x=14-6
x=8
there fore
numerator will be8
and denominator will be 11
so,number=8/11
I believe this will help u :)
let numerator =x
denominator =x+3
number=x/x+3
If the numerator is increased by 7 and denominator decreases by 1 the new number is 3/2
so,x+ 7/x+3-1=3/2
x+7/x+2=3/2
2(x+7)=3(x+2)
2x+14=3x+6
3x-2x=14-6
x=8
there fore
numerator will be8
and denominator will be 11
so,number=8/11
I believe this will help u :)
Answered by
0
Hii friend,
let the numerator be x
let the denominator be x+3
new numerator = x+7
new denominator = x+2
BTP,
x+7/x+2=3/2
2x+14=3x+6
2x-3x=6-14
-x=-8
x=8
THEREFORE,
Numerator=8
Denominator=11 (8+3)
The required fraction is 8/11
________________________________________________________________________________________________________________________________________________
HOPE THIS HELPS U...☺
let the numerator be x
let the denominator be x+3
new numerator = x+7
new denominator = x+2
BTP,
x+7/x+2=3/2
2x+14=3x+6
2x-3x=6-14
-x=-8
x=8
THEREFORE,
Numerator=8
Denominator=11 (8+3)
The required fraction is 8/11
________________________________________________________________________________________________________________________________________________
HOPE THIS HELPS U...☺
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