the denominator of a rational number is greater than its numerator by 3 in 3 is subtracted from the numerator and 2 is added to the nominal the new number becomes 1 by 5 find the original number check your solution
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let n = numerator
n+3 = denominator
n-3/n+3+2 = 1/5
n-3/n+5 = 1/5
5(n-3) = n+5
5n-15 = n+5
4n = 20
n= 5
n+3 = 8
original no = 5/8
n+3 = denominator
n-3/n+3+2 = 1/5
n-3/n+5 = 1/5
5(n-3) = n+5
5n-15 = n+5
4n = 20
n= 5
n+3 = 8
original no = 5/8
Answered by
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Solution:
Given: The denominator is grater than numerator by 3.
So,Let the numerator be x,
then,the denominator is x+3... x/(x+3)
when 3 is subtracted from numerator and 2 is added to the denominator,it becomes1/5..
which means, (x-3)/(x+3+2)=1/5
(x-3)/(x+5)=1/5
5(x-3)=x+5
5x-15=x+5
5x-10=x
5x-x=10
4x=10
x=10/4...numerator is 10/4
x+3=10/4+3
x+3=10/4+12/4
x+3=22/4...... denominator is 22/4
∴The fraction (x/x+3) (10/4/22/4)=>10/22=>5/11
Given: The denominator is grater than numerator by 3.
So,Let the numerator be x,
then,the denominator is x+3... x/(x+3)
when 3 is subtracted from numerator and 2 is added to the denominator,it becomes1/5..
which means, (x-3)/(x+3+2)=1/5
(x-3)/(x+5)=1/5
5(x-3)=x+5
5x-15=x+5
5x-10=x
5x-x=10
4x=10
x=10/4...numerator is 10/4
x+3=10/4+3
x+3=10/4+12/4
x+3=22/4...... denominator is 22/4
∴The fraction (x/x+3) (10/4/22/4)=>10/22=>5/11
sivaprasath:
hey,that's 5x-20=x,sorry. so, x=5,..x+3=5+3=8
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