the denominator of a rational number is greater than its numerator by 3 if numerator is increased by 14 and denominator is decreased by 3 the new number becomes 11 upon 4 what is the original number
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Answered by
2
Hii....☺
Here is your answer......
♦Let the Numerator of the fraction be x
♦ Denominator = x + 3
⭐ Now, according to the given condition we have:
=> x + 14 / x + 3 - 3 = 11/4
=> x + 14 / x = 11/4
=> 4( x + 14 ) = 11x
=> 4x + 56 = 11x
=> 11x - 4x = 56
=> 7x = 56
=> x = 8
⭐ Numerator of the fraction = 8
⭐ Denominator = x + 3 = 8 + 3 = 11
♦ Hence, original fraction = 8/11
Thanks....☺
Hope this helps you....☺
Here is your answer......
♦Let the Numerator of the fraction be x
♦ Denominator = x + 3
⭐ Now, according to the given condition we have:
=> x + 14 / x + 3 - 3 = 11/4
=> x + 14 / x = 11/4
=> 4( x + 14 ) = 11x
=> 4x + 56 = 11x
=> 11x - 4x = 56
=> 7x = 56
=> x = 8
⭐ Numerator of the fraction = 8
⭐ Denominator = x + 3 = 8 + 3 = 11
♦ Hence, original fraction = 8/11
Thanks....☺
Hope this helps you....☺
shreshth71:
thanka veronika
Answered by
0
let the numerator be x .
and denominator will be x+3 .
A/Q
( x ) + 14 / ( x+3 ) - 3 = 11 / 4
x + 14 / x + 0 = 11 / 4. cross multiply
4x + 56 = 11x by transposing
56 = 11x - 4x
56 = 7x
56 / 7 = x
8 = x
since , put the values
numerator = x = 8 and ,
denominator = x+3 = 8+3 = 11
so the fraction is 8 / 11 .......
and denominator will be x+3 .
A/Q
( x ) + 14 / ( x+3 ) - 3 = 11 / 4
x + 14 / x + 0 = 11 / 4. cross multiply
4x + 56 = 11x by transposing
56 = 11x - 4x
56 = 7x
56 / 7 = x
8 = x
since , put the values
numerator = x = 8 and ,
denominator = x+3 = 8+3 = 11
so the fraction is 8 / 11 .......
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