Question

the denominator of fraction is 3 less than the numerator ,. increasing the numareter by 4, and decreasing the denominetor by 3 we get the number 3 find the fraction​

Answer 1

Correct Question

The denominator of fraction is 3 less than the numerator. Increasing the numerator by 4, and decreasing the denominator by 3 we get the number 3. Find the fraction.

Answer:-

Let the numerator be x

Then denominator will be x - 3 ...(ATQ)

Original fraction = $\rm\dfrac{x}{x-3}$

ATQ, now,

Increasing the numerator by 4, and decreasing the denominator by 3 we get the number 3.

Hence,

$\dashrightarrow\rm\dfrac{x+4}{(x-3)-3} = 3$

$\dashrightarrow\rm\dfrac{x+4}{x-3-3} = 3$

$\dashrightarrow\rm\dfrac{x+4}{x-6} = 3$

$\dashrightarrow\rm 3(x-6) = x+4$

$\dashrightarrow\rm 3x-18= x+4$

$\dashrightarrow\rm 3x-x= 18+4$

$\dashrightarrow\rm 2x= 22$

$\dashrightarrow\rm x= \dfrac{22}{2}$

$\dashrightarrow\rm x= 11$

Original fraction

$\dashrightarrow\rm\dfrac{x}{x-3}\\\\\rm\dashrightarrow\dfrac{11}{11-3} =\dfrac{11}{8}$

Hence, the original fraction is 11/8.