the denominator of r.n. is greater than its numerator by 3 . if 3 is subtracted from the numerator and 2 is added to the denominator the new no. becomes 1/5 find the original no.
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Answer:
x−3
=
5
1
\begin{lgathered}\frac{x - 3}{x + 5} = \frac{1}{5} \\ \\ 5(x - 3) = 1(x + 5) \\ \\ 5x - 15 = x + 5 \\ \\ 5x - x = 5 + 15 \\ \\ 4x = 20 \\ \\ x = \frac{20}{4} \\ \\ x = 5\end{lgathered}
x+5
x−3
=
5
1
5(x−3)=1(x+5)
5x−15=x+5
5x−x=5+15
4x=20
x=
4
20
x=5
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