THE DENOMINATORS OF A FRCTIONS IS 7 MORE THANS ITS NUMERATORS IF 3 IS ADDED TO THE DENOMINATOR AND 5 IS ADDED TO THE NUMERATORS THEN THE NEW FRACTION IS 3/4 FIND THE ORIGINALS FRACTION
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Answer:
Let x=numerator,
y=denominator.
y=x+7-
(x+3)/(y+3) = 2/3
(Cross multiply)
3(x+3)=2(y+3)
3x+9=2y+6
(subtract 9 from both sides)
3x+9-9-2y+6-9
3x-2y+6-9
3x=2y-3 - (ii)
(substitute the value of equation (i) into (ii))
3x=2(x+7)-3
3x-2x+14-3
3x=2x+11
(subtract 2x from both sides)
3x-2x=2x+11-2x
X=11.
(substitute the value of x into equation (i))
y=7+11
y=18.
• so numerator = 11,
denominator = 18.
• So original fraction is 11/18.
• 3/11th of original fraction is
= 11/18 x 3/11
= (11x3)/(18x11)
= 3/18
=1/6.
Answer = 1/6
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