Question

The density (in g mL⁻¹) of a 3.60 M sulphuric acid solution that is 29% H₂SO₄ (molar mass = 98 g mol⁻¹) by mass will be
(a) 1.45
(b) 1.64
(c) 1.88
(d) 1.22

Answer 1

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➡️Option -: D✔️✔️

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Answer 2

Answer:

From the given options, the correct option is (d) 1.22.

Explanation:

Using the mass percentage formula, we can calculate the mass of sulphuric acid and the number of moles. We will calculate the density of the solution using the molarity formula.

Formula used:

Molarity=no. of moles/volume of solution(ml)

×1000

no. of moles=mass/molar mass

Complete the following step-by-step answer:

The concentration is sometimes expressed as a percentage. In terms of percentage, there are two ways to represent concentration: percentage by mass and percentage by volume. When neither of them is specified in the question, we will assume that the percentage by mass is given to us.

Percentage by mass is defined as the mass of solute present in 100 gramme of solution.

The mass percentage of H2SO4 is given to us as 29%, implying that 29 g of H2SO4 is contained in 100 g of solution.

moles of H2SO4=mass/molar mass

By combining the values, we can calculate the number of moles of sulphuric acid as follows: moles of H2SO4=2998=0.2959 mole

H2SO4 has a mass of 29 g. H2SO4's molar mass is 21+32+416=98.

We know that density=massvolume.

By rearranging the equations, we get: volume of solution=mass of solutiondensity of solution.

We will get by substituting the values in the molarity formula,

Molarity=moles of H2SO4mass of solution×density of solution×1000

We can rearrange the equation to get more simplified version as:

density of solution=Molarity×mass of solution / moles of H2SO4×1000

⇒density=3.6×100/0.2959×1000=1.22g ml−1

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