The density (in g mL–1) of a 3.60 M sulphuric acid solution that is 29% H2SO4 (Molar mass = 98 g mol–1) by mass will be
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100g solution contains 29g H2SO4H2SO4
Let the density of solution (in g/ml) is d
Molarity of solution=Moles of H2SO4Volume of solution(ml)Moles of H2SO4Volume of solution(ml)×1000×1000
(M=3.60)
2998100d2998100d×1000=3.60×1000=3.60
d=1.22g/mld=1.22g/ml
Let the density of solution (in g/ml) is d
Molarity of solution=Moles of H2SO4Volume of solution(ml)Moles of H2SO4Volume of solution(ml)×1000×1000
(M=3.60)
2998100d2998100d×1000=3.60×1000=3.60
d=1.22g/mld=1.22g/ml
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