the density of 1M solution ofNaCl is 1.0585g per ml .the molality of the solution is
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heya, here is ur answer ^_^
Take a hypothetical sample of 1.000 L of the solution.
(1.000 L) x (1 mol/L) x (58.4430 g NaCl/mol) = 58.4430 g NaCl
(1000 mL) x (1.0585 g/mL) = 1058.5 g total
(1058.5 g - 58.4430 g NaCl) = 1000.057 g H2O
(1.000 L) x (1 mol/L) = 1.000 mol NaCl
(1.000 mol) / (1000.057 g / 1000 g) =
(1.00000 mol) / ((1 000.057 g) / (1000 g)) = 1.000 mol/1000 g = 1.0 m
IF IT'S HELP YOU PLEASE MARK AS BRAINLIEST
Take a hypothetical sample of 1.000 L of the solution.
(1.000 L) x (1 mol/L) x (58.4430 g NaCl/mol) = 58.4430 g NaCl
(1000 mL) x (1.0585 g/mL) = 1058.5 g total
(1058.5 g - 58.4430 g NaCl) = 1000.057 g H2O
(1.000 L) x (1 mol/L) = 1.000 mol NaCl
(1.000 mol) / (1000.057 g / 1000 g) =
(1.00000 mol) / ((1 000.057 g) / (1000 g)) = 1.000 mol/1000 g = 1.0 m
IF IT'S HELP YOU PLEASE MARK AS BRAINLIEST
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