Question

The density of 2.05 m solution of acetic acid of the water is 1.02 gram per ml determine the molality of the solution

Answer 1

Answer:

17 mole

Explanation:

volume =2.05

molecular mass=60

weight of solute=2.091

we know ,

W=SVM÷1000

S is molarity,M is molecular mass,W is weightvof solute and V is volume

Answer 2

Answer:

  m = 2.285mol kg⁻¹

Explanation:

molality - m

molarity - M

Density - d

M₂ - Molecular mass - CH₃COOH = 60g

m = 1000M / 1000d - MM₂

m = 1000 × 2.05 / (1000 × 1.02) - (2.05 × 60)

m = 2050 / 1020 - 123

m = 2050 / 897

m = 2.285mol kg⁻¹