The density of 2M solution of a solute is 1. 2g/ml. If the molecular weight of the solute is 100g/mol then the molality of tge solution is
a)2 b)1. 2 c)1 d)0. 6 e)2. 4
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There is a straight formula for converting w/w% into molarity.
Molarity={(w/w%)×10×(density in g/ml)}÷(Molar mass of solute in g)
Putting values, M=(98×10×1.8)/(98)=18M
Now, Normality=Molarity×n-factor
Putting values, N=18×2=36N (n-factor is 2 because H2SO4 is a dibasic acid)
Molality is a bit tricky because the formula involves tedious calculation.
Molality=(1000×Molarity)/{(1000×density in g/ml)-(Molar mass of solute in g×Molarity)}
Putting values,
m=(1000×18)/{(1000×1.8)-(98×18)}
=18000/(1800–1764)
=18000/36=500m
Molarity={(w/w%)×10×(density in g/ml)}÷(Molar mass of solute in g)
Putting values, M=(98×10×1.8)/(98)=18M
Now, Normality=Molarity×n-factor
Putting values, N=18×2=36N (n-factor is 2 because H2SO4 is a dibasic acid)
Molality is a bit tricky because the formula involves tedious calculation.
Molality=(1000×Molarity)/{(1000×density in g/ml)-(Molar mass of solute in g×Molarity)}
Putting values,
m=(1000×18)/{(1000×1.8)-(98×18)}
=18000/(1800–1764)
=18000/36=500m
ParuPavi:
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