Question

The density of 3.0M solution of sodium chloride 1.25 g/ml. Find the amount of solute present in 1000 g of solvent.
1) 2.79 mol
2) 3.1 mol
3) 2.99 mol
4)3.01 mol​

Answer 1

Answer:

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3 Molar solution means there are 3 moles of NaCl salt in 1 Liter. Molecular weight of NaCl = 58.44.

Hence, there are 3×58.44 gms in 1 Litre of water.

Density =

volume

mass

Mass of 1 litre of solution = 1.25 gms/ml * 1000 ml = 1, 250 gms

V = volume of water added to make the solution

175.32 gms + 1 gm /ml * V = 1, 250 gm

⟹V=1,074.68ml

So 1,074.68 ml or 1, 074.68 gms of water is mixed with 3 moles of Na Cl to make the 3 M solution.

Molality = mass of solute in number of moles / mass of solvent in kg

=

1.07468

3

kg

=2.7915 Molal