The density of 3 M soluti on of NaCl is 1.25 g mL-1. Calculate molality of the solution. NCERT Class XII Chemistry - Main Course Book I Chapter 1. Some Basic Conpepts of Chemistry
Answers
Answered by
1
this formula will be very helpful in competitive exams. remember it. hope this helps.
Attachments:
Answered by
1
given, density=1.25gm/ml
mole=3
mole of solute=3
volume of solution=1000ml
mass of solution=vol*density
=1000*1.25
=1250gm
mass of solute=>mole=weight/mm
=>3=x/58=>174gm
mass of solvent=1250-174=1076gm
Now, Molality=Moles of solute/weight of solvent in kg
=3/1076÷1000
=3/1.076
=2.7881
=2.79(approximate..)
mole=3
mole of solute=3
volume of solution=1000ml
mass of solution=vol*density
=1000*1.25
=1250gm
mass of solute=>mole=weight/mm
=>3=x/58=>174gm
mass of solvent=1250-174=1076gm
Now, Molality=Moles of solute/weight of solvent in kg
=3/1076÷1000
=3/1.076
=2.7881
=2.79(approximate..)
Similar questions