Question

The density of 3 molal solution of NaCl is 1.110 g mL–1. Calculate the molarity of the solution.


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Answer 1

Answer:

Molality of NaOH solution =3 m

Molality=number of moles of solute/mass of solvent(kg)

3=

massofsolvent

n

mass of solvent =

3

1000n

g

Also, number of moles=mass/molar mass

For NaOH solution, n=

40

m

Density of solution,ρ=1.110g/mL

Mass of 1 mL solution =1.11g=m

solute

+m

solvent

3

n×40+1000n

=1.11

n=2.97×10

−3

mol

Molarity = number of moles of solute/ volume of solution(L)

M=

0.001

2.97×10

−3

=2.97M