The density of 3 molal solution of naoh is 1.110 g ml^-1. Calculate the molarity of the solution
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Answer:
2.97 M
Explanation:
You have to go by the formula,
m= 1000M/[1000d-M(Mol.wt)]
3=1000M/[1000(1.110)-M(40)]
3330-120M=1000M
3330=1120M
therefore,
M=3330/1120=2.97M
hope it helps:)
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